解:①根据题意,知Hmax=125mm,Hq=90mm,󠄐󠄹󠅀󠄪󠄣󠄞󠄡󠄤󠄥󠄞󠄩󠄩󠄞󠄡󠄧󠄨󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
$$V_{max}\leq \sqrt{\frac{(H_{max}+H_q)R}{11.8}}\leqslant \sqrt{\frac{(125+90)*600}{11.8}}\leq 104.55km/h$$󠄐󠄹󠅀󠄪󠄣󠄞󠄡󠄤󠄥󠄞󠄩󠄩󠄞󠄡󠄧󠄨󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
③该曲线需要限速,限速100km/h。󠄐󠄹󠅀󠄪󠄣󠄞󠄡󠄤󠄥󠄞󠄩󠄩󠄞󠄡󠄧󠄨󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
④超高顺坡率i=1/7Vmax=1/7×100=1.4‰󠄐󠄹󠅀󠄪󠄣󠄞󠄡󠄤󠄥󠄞󠄩󠄩󠄞󠄡󠄧󠄨󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
⑤顺坡长度L=H/i=125/1.4=89.286m󠄐󠄹󠅀󠄪󠄣󠄞󠄡󠄤󠄥󠄞󠄩󠄩󠄞󠄡󠄧󠄨󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
⑥因为缓和曲线长度只有80m,则125-80×1.4=13mm󠄐󠄹󠅀󠄪󠄣󠄞󠄡󠄤󠄥󠄞󠄩󠄩󠄞󠄡󠄧󠄨󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
⑦有13mm超高需在直线上顺坡.󠄐󠄹󠅀󠄪󠄣󠄞󠄡󠄤󠄥󠄞󠄩󠄩󠄞󠄡󠄧󠄨󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
计算精确,分析到位!