某段线路钢轨为60kg/m,每根长为25m,配轨枕46根,接头轨枕间距为540mm,求轨枕间距。(设轨缝为8mm)󠄐󠄹󠅀󠄪󠄡󠄨󠄞󠄢󠄡󠄧󠄞󠄠󠄞󠄢󠄤󠄢󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
解:由a=(L’-2c)/(n-2)知󠄐󠄹󠅀󠄪󠄡󠄨󠄞󠄢󠄡󠄧󠄞󠄠󠄞󠄢󠄤󠄢󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
a=(25.008-2×0.54)/(46-2)=0.544m=544mm󠄐󠄹󠅀󠄪󠄡󠄨󠄞󠄢󠄡󠄧󠄞󠄠󠄞󠄢󠄤󠄢󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
b=[L’-c-(n-3)a]/2=(25.008-0.54-(46-3)×0.544)/2=0.538m=538mm󠄐󠄹󠅀󠄪󠄡󠄨󠄞󠄢󠄡󠄧󠄞󠄠󠄞󠄢󠄤󠄢󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮
答:过渡间距为538mm,其余轨枕间距为544mm。󠄐󠄹󠅀󠄪󠄡󠄨󠄞󠄢󠄡󠄧󠄞󠄠󠄞󠄢󠄤󠄢󠄬󠅒󠅢󠄟󠄮󠄐󠅅󠄹󠄴󠄪󠄾󠅟󠅤󠄐󠄼󠅟󠅗󠅙󠅞󠄬󠅒󠅢󠄟󠄮󠇘󠆭󠆘󠇙󠆝󠅵󠇗󠆭󠆁󠄐󠇗󠅹󠅸󠇖󠆍󠅳󠇖󠅹󠅰󠇖󠆌󠅹󠄬󠅒󠅢󠄟󠄮